document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=393589>Question 393589</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The cost of a membership to a health club has an initiation fee and monthly dues. If the club charges $100 for 2 months and $200 for 6 months, then find the initiation cost and the monthly dues fees. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #279310 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=279310\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let i = initiation fee, m = monthly fee.\r<BR>\n" );
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document.write( "Then we get the system<BR>\n" );
document.write( "i + 2m = 100 <--(1)<BR>\n" );
document.write( "i + 6m = 200 <--(2)<BR>\n" );
document.write( "Subtracting the top equation from the bottom equation, we get\r<BR>\n" );
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document.write( "4m = 100, or m = $25, the monthly fee.<BR>\n" );
document.write( "The initiation fee is i + 2*25 = 100,<BR>\n" );
document.write( "==> i = 100 - 50 = $50 </SPAN>\n" );
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