document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=393541>Question 393541</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a spice mixture is 25% thyme.How many grams of thyme must be added to a 12 g. of mixture to increase the thyme content to 40%? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #279273 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=279273\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a spice mixture is 25% thyme.How many grams of thyme must be added to a 12 g. of mixture to increase the thyme content to 40%?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "thyme + thyme = thyme<BR>\n" );
document.write( "0.25x + 1.0(12-x) = 0.40*12<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "25x + 100*12-100x = 40*12<BR>\n" );
document.write( "-75x = -60*12<BR>\n" );
document.write( "x = 9.6 g (amt of 25% mixture needed in the final mix)<BR>\n" );
document.write( "12-x = 2.4 g (amt of pure thyme needed in the final mix)<BR>\n" );
document.write( "===============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );