document.write( "Question 393385: Exoponential Method
\n" ); document.write( "1.A biologist is researching a newly-discovered species of bacteria. at time t=0 hours, he puts one hundred bacteria into what he has determined to be a favorable growth medium. Six hours later, he measures 450 bacteria. Find an exponential equation thet approximates the information.\r
\n" ); document.write( "\n" ); document.write( "2. A $1,000 deposit is made at a bank that pays 12% compound monthly. How much will you havein your account at the end of 10 years.
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Algebra.Com's Answer #279211 by ankor@dixie-net.com(22740)\"\" \"About 
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1.A biologist is researching a newly-discovered species of bacteria.
\n" ); document.write( " at time t=0 hours, he puts one hundred bacteria into what he has determined to
\n" ); document.write( " be a favorable growth medium.
\n" ); document.write( " Six hours later, he measures 450 bacteria.
\n" ); document.write( " Find an exponential equation that approximates the information.
\n" ); document.write( ":
\n" ); document.write( "find k, the growth factor
\n" ); document.write( "100*(2^(6/k)) = 450
\n" ); document.write( "Divide both sides by 100
\n" ); document.write( "2^(6/k) = 4.5
\n" ); document.write( "use logs here
\n" ); document.write( "log(2^(6/k)) = log(4.5)
\n" ); document.write( ":
\n" ); document.write( "\"6%2Fk\"log(2) = log(4.5)
\n" ); document.write( "\"6%2Fk\" = \"log%284.5%29%2Flog%282%29\"
\n" ); document.write( "\"6%2Fk\" = 2.17
\n" ); document.write( "k = \"6%2F2.17\"
\n" ); document.write( "k = 2.765 is the growth factor
\n" ); document.write( ":
\n" ); document.write( "A = Ao*2^(t/2.765), the exponential equation
\n" ); document.write( "where
\n" ); document.write( "Ao = initial amt
\n" ); document.write( "A = amt after t hrs
\n" ); document.write( "t = time in hrs
\n" ); document.write( ":
\n" ); document.write( "Check equation using Ao = 100: In a calc enter: 100*2^(6/2.765) results: 450.0
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\n" ); document.write( ":
\n" ); document.write( "2. A $1,000 deposit is made at a bank that pays 12% compound monthly.
\n" ); document.write( " How much will you have in your account at the end of 10 years.
\n" ); document.write( ":
\n" ); document.write( "Compound interest formula:
\n" ); document.write( "A =\"p%281%2Br%2Fn%29%5E%28nt%29%29\"
\n" ); document.write( "where
\n" ); document.write( "A = resulting amt after t years
\n" ); document.write( "P = principal ($1000)
\n" ); document.write( "r = interest rate in decimals (.12)
\n" ); document.write( "n = no. of time compounded per yr (12 times/yr)
\n" ); document.write( "t = no. of yrs (10 yrs)
\n" ); document.write( ":
\n" ); document.write( "A =\"1000%281%2B.12%2F12%29%5E%2812%2A10%29%29\"
\n" ); document.write( ":
\n" ); document.write( "A =\"1000%281%2B.01%29%5E%28120%29%29\"
\n" ); document.write( ":
\n" ); document.write( "A =\"1000%281.01%29%5E%28120%29%29\"
\n" ); document.write( "on a calc
\n" ); document.write( "A = $3300.39
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