document.write( "Question 393385: Exoponential Method
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document.write( "1.A biologist is researching a newly-discovered species of bacteria. at time t=0 hours, he puts one hundred bacteria into what he has determined to be a favorable growth medium. Six hours later, he measures 450 bacteria. Find an exponential equation thet approximates the information.\r
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document.write( "2. A $1,000 deposit is made at a bank that pays 12% compound monthly. How much will you havein your account at the end of 10 years.
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Algebra.Com's Answer #279211 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! 1.A biologist is researching a newly-discovered species of bacteria. \n" ); document.write( " at time t=0 hours, he puts one hundred bacteria into what he has determined to \n" ); document.write( " be a favorable growth medium. \n" ); document.write( " Six hours later, he measures 450 bacteria. \n" ); document.write( " Find an exponential equation that approximates the information. \n" ); document.write( ": \n" ); document.write( "find k, the growth factor \n" ); document.write( "100*(2^(6/k)) = 450 \n" ); document.write( "Divide both sides by 100 \n" ); document.write( "2^(6/k) = 4.5 \n" ); document.write( "use logs here \n" ); document.write( "log(2^(6/k)) = log(4.5) \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "k = \n" ); document.write( "k = 2.765 is the growth factor \n" ); document.write( ": \n" ); document.write( "A = Ao*2^(t/2.765), the exponential equation \n" ); document.write( "where \n" ); document.write( "Ao = initial amt \n" ); document.write( "A = amt after t hrs \n" ); document.write( "t = time in hrs \n" ); document.write( ": \n" ); document.write( "Check equation using Ao = 100: In a calc enter: 100*2^(6/2.765) results: 450.0 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "2. A $1,000 deposit is made at a bank that pays 12% compound monthly. \n" ); document.write( " How much will you have in your account at the end of 10 years. \n" ); document.write( ": \n" ); document.write( "Compound interest formula: \n" ); document.write( "A = \n" ); document.write( "where \n" ); document.write( "A = resulting amt after t years \n" ); document.write( "P = principal ($1000) \n" ); document.write( "r = interest rate in decimals (.12) \n" ); document.write( "n = no. of time compounded per yr (12 times/yr) \n" ); document.write( "t = no. of yrs (10 yrs) \n" ); document.write( ": \n" ); document.write( "A = \n" ); document.write( ": \n" ); document.write( "A = \n" ); document.write( ": \n" ); document.write( "A = \n" ); document.write( "on a calc \n" ); document.write( "A = $3300.39 \n" ); document.write( " |