document.write( "Question 393414: the absolute value of 3x+1 is greater than or equal to 11
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document.write( "answer in interval notation \n" );
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Algebra.Com's Answer #279210 by edjones(8007)![]() ![]() You can put this solution on YOUR website! |3x+1|>=11 \n" ); document.write( ". \n" ); document.write( "3x+1>=11 \n" ); document.write( "3x>=10 \n" ); document.write( "x>=10/3 \n" ); document.write( ". \n" ); document.write( "3x+1<=-11 \n" ); document.write( "3x<=-12 \n" ); document.write( "x<=-4 \n" ); document.write( ". \n" ); document.write( "(-infinity, -4]U[10/3, infinity] \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " |