document.write( "Question 393387: loan= $500,000
\n" ); document.write( "part A = 6% each year
\n" ); document.write( "part B = 11% each year\r
\n" ); document.write( "\n" ); document.write( "if the bank recieves $43,750 in interest each year, how much was loaned at 6%?
\n" ); document.write( "

Algebra.Com's Answer #279193 by stanbon(75887)\"\" \"About 
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loan= $500,000
\n" ); document.write( "part A = 6% each year
\n" ); document.write( "part B = 11% each year
\n" ); document.write( "if the bank recieves $43,750 in interest each year, how much was loaned at 6%?
\n" ); document.write( "------------------------
\n" ); document.write( "Equations:
\n" ); document.write( "Quantity Eq::: x + y = 500,000
\n" ); document.write( "---
\n" ); document.write( "Interest Eq::0.11x + 0.06y = 43,750
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\n" ); document.write( "Multiply thru the 1st by 11.
\n" ); document.write( "Multiply thru the 2nd by 100.
\n" ); document.write( "--------------------------------
\n" ); document.write( "11x + 11y = 11*500,000
\n" ); document.write( "11x + 6y = 4375000
\n" ); document.write( "-----------------------------
\n" ); document.write( "Subtract the 2nd from the 1st and solve for \"y\":
\n" ); document.write( "5y = 1,125,000
\n" ); document.write( "---
\n" ); document.write( "y = $225,000 (amt. invested at 6%)
\n" ); document.write( "=================
\n" ); document.write( "500,000- 225,000 = 275,000 (amt. invested at 11%
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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