document.write( "Question 393361: Arthur can edit 15 essays in 10 h. Debra needs 15 h to do the same job. If they work together, how long will it take them to edit the essays? \n" ); document.write( "
Algebra.Com's Answer #279172 by stanbon(75887)\"\" \"About 
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Arthur can edit 15 essays in 10 h. Debra needs 15 h to do the same job. If they work together, how long will it take them to edit the essays?
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\n" ); document.write( "Arthur DATA:
\n" ); document.write( "time = 10 hr/job ; rate = 1/10 job/hr
\n" ); document.write( "-------
\n" ); document.write( "Debra DATA:
\n" ); document.write( "time = 15 hr/job ; rate = 1/15 job/hr
\n" ); document.write( "--------
\n" ); document.write( "Together DATA:
\n" ); document.write( "time = x hr/job ; rate = 1/x job/hr
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\n" ); document.write( "Equation:
\n" ); document.write( "rate + rate = together rate
\n" ); document.write( "1/10 + 1/15 = 1/x
\n" ); document.write( "---
\n" ); document.write( "Multiply thru by 30x to get:
\n" ); document.write( "3x + 2x = 30
\n" ); document.write( "5x = 30
\n" ); document.write( "x = 6 hrs (amt. of time needed for them to do the job together)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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