document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=393359>Question 393359</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the standard form of the equation of the line that passes through the points (9,-3) and (-1,-7) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #279171 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=279171\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find the standard form of the equation of the line that passes through the points (9,-3) and (-1,-7)<BR>\n" );
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document.write( "slope = (-7--3)/(-1-9) = -4/-10 = 2/5<BR>\n" );
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document.write( "Form: y = mx+b<BR>\n" );
document.write( "You have y = -3 when x=9 and m = 2/5<BR>\n" );
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document.write( "-3 = (2/5)(9)+b<BR>\n" );
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document.write( "b = -3-(2/5)9<BR>\n" );
document.write( "b = -6.6<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "y = (2/5)x - (33/5)<BR>\n" );
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document.write( "To get the standard form, multiply thru by 5 to get:<BR>\n" );
document.write( "5y = 2x - 33<BR>\n" );
document.write( "-2x+5y = -33<BR>\n" );
document.write( "====================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( "=========== </SPAN>\n" );
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