document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=393357>Question 393357</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A goldsmith has two alloys of gold, the first being 70% pure and the second being 60% pure. How many ounces of the 60% pure gold must be used to make 100 ounces of an alloy which will be 66% gold?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #279169 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=279169\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A goldsmith has two alloys of gold, the first being 70% pure and the second being 60% pure. How many ounces of the 60% pure gold must be used to make 100 ounces of an alloy which will be 66% gold?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "gold + gold = gold<BR>\n" );
document.write( "0.70x + 0.60(100-x) = 0.66*100<BR>\n" );
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document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "70x + 60*100 - 60x = 66*100<BR>\n" );
document.write( "10x = 6*100<BR>\n" );
document.write( "x = 60 oz (amt. of 70% alloy needed in the mix)<BR>\n" );
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document.write( "100-x = 40 oz (amt of 60% alloy needed in the mix)<BR>\n" );
document.write( "==============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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