document.write( "Question 393202: Two pumps of different sizes working together can empty a tank in 3 hours. The larger pump can empty this tank in 5 hours. How long will it take the smaller one to do the job alone? Show the 4-step process. \n" ); document.write( "
Algebra.Com's Answer #279144 by ankor@dixie-net.com(22740)\"\" \"About 
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Two pumps of different sizes working together can empty a tank in 3 hours.
\n" ); document.write( " The larger pump can empty this tank in 5 hours.
\n" ); document.write( " How long will it take the smaller one to do the job alone?
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\n" ); document.write( "Let t = time required by the small pump alone
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\n" ); document.write( "Let the completed job = 1 (an empty tank)
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\n" ); document.write( "Each pump will do a fraction of the job, the two fractions add up to 1
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\n" ); document.write( "\"3%2F5\" + \"3%2Ft\" = 1
\n" ); document.write( "Multiply by 5t, results
\n" ); document.write( "3t + 5(3) = 5t
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\n" ); document.write( "15 = 5t - 3t
\n" ); document.write( "15 = 2t
\n" ); document.write( "t = \"15%2F2\"
\n" ); document.write( "t = 7.5 hrs, the small pump alone
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\n" ); document.write( "Check the solution
\n" ); document.write( "\"3%2F5\" + \"3%2F7.5\" =
\n" ); document.write( ".6 + .4 = 1; confirms our solution
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