document.write( "Question 393202: Two pumps of different sizes working together can empty a tank in 3 hours. The larger pump can empty this tank in 5 hours. How long will it take the smaller one to do the job alone? Show the 4-step process. \n" ); document.write( "
Algebra.Com's Answer #279144 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! Two pumps of different sizes working together can empty a tank in 3 hours. \n" ); document.write( " The larger pump can empty this tank in 5 hours. \n" ); document.write( " How long will it take the smaller one to do the job alone? \n" ); document.write( ": \n" ); document.write( "Let t = time required by the small pump alone \n" ); document.write( ": \n" ); document.write( "Let the completed job = 1 (an empty tank) \n" ); document.write( ": \n" ); document.write( "Each pump will do a fraction of the job, the two fractions add up to 1 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "Multiply by 5t, results \n" ); document.write( "3t + 5(3) = 5t \n" ); document.write( ": \n" ); document.write( "15 = 5t - 3t \n" ); document.write( "15 = 2t \n" ); document.write( "t = \n" ); document.write( "t = 7.5 hrs, the small pump alone \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check the solution \n" ); document.write( " \n" ); document.write( ".6 + .4 = 1; confirms our solution \n" ); document.write( " |