document.write( "Question 393261: When one number is 2 more than twice another and their product is 2 more than twice their sum, what is the two number solution? I used x to represent one number and 2x + 2, which equals to x(2x + 2)= 2 + 2x + 2 = 2x^2 + 2x = 2x + 4, therefore, 2x^2 + 2x-2x = -4, 2x^2 = -4 = (2x-2)(x+2). Answer: 2 and -2? \n" ); document.write( "
Algebra.Com's Answer #279124 by stanbon(75887)\"\" \"About 
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When one number is 2 more than twice another and their product is 2 more than twice their sum, what is the two number solution?
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\n" ); document.write( "Let one number be \"x\".
\n" ); document.write( "The other number is \"2x+2\"
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\n" ); document.write( "Equation:
\n" ); document.write( "x(2x+2) = 2(x+2x+2) + 2
\n" ); document.write( "2x^2 + 2x = 2x+4x+4 + 2
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\n" ); document.write( "2x^2 + 2x = 6x+6
\n" ); document.write( "2x^2-4x-6 = 0
\n" ); document.write( "Factor:
\n" ); document.write( "2x^2-6x+2x-6 = 0
\n" ); document.write( "2x(x-3)+2(x-3) = 0
\n" ); document.write( "(x-3)(2x+2) = 0
\n" ); document.write( "Positive solution:
\n" ); document.write( "x = 3
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\n" ); document.write( "1st number: x = 3
\n" ); document.write( "2nd number: 2x+2 = 2*3+2 = 8
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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