document.write( "Question 393159: in a recent poll 70% of the surveyed said that they will not go away on vacation this year. if three people are randomly selected, what is the probability that all 3 will not go away on vacation this year \n" ); document.write( "
Algebra.Com's Answer #279090 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi
\n" ); document.write( "Note: The probability of x successes in n trials is:
\n" ); document.write( "P = nCx* \"p%5Ex%2Aq%5E%28n-x%29\" where p and q are the probabilities of success and failure respectively.
\n" ); document.write( "In this case p(not going on vacation)= .70 and q = .30
\n" ); document.write( "nCx = \"n%21%2F%28x%21%28n-x%21%29%29\"
\n" ); document.write( "P(3 selected not going on vacation) = (.70)^3 = .343 \n" ); document.write( "
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