Algebra.Com's Answer #279089 by Edwin McCravy(20060)  You can put this solution on YOUR website! Find the equation of the line normal to the curve  \n" );
document.write( "at the point (3,1). \n" );
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document.write( "First we find the derivative of the curve using the implicit method:\r\n" );
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document.write( "Rewrite that so that the denominator becomes a negative exponent \r\n" );
document.write( "in the top:\r\n" );
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document.write( "Divide both sides by 2:\r\n" );
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document.write( "Divide both sides by y:\r\n" );
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document.write( "Substitute the point (3,1)\r\n" );
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document.write( "So the slope of a tangent line to the graph at the point (3,1)\r\n" );
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document.write( "would be \r\n" );
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document.write( "Therefore the slope of a line normal (perpendicular) to the\r\n" );
document.write( "curve at that point has a slope which is the reciprocal of that\r\n" );
document.write( "slope with the opposite sign which would be \r\n" );
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document.write( "So we want the equation of the line with slope that\r\n" );
document.write( "passes through (3,1)\r\n" );
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document.write( "Multiply through by 4\r\n" );
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document.write( "Divide through by 4\r\n" );
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document.write( "Now we graph that line in blue:\r\n" );
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document.write( "and we see that it looks perpendicular to the curve at the\r\n" );
document.write( "point (3,1). Especially does it look perpendicular to the \r\n" );
document.write( "curve if we also draw the tangent line (in green):\r\n" );
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document.write( "Edwin \n" );
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