document.write( "Question 393165: A poll found that 45% of the workers at the company take the bus instead of the car to work to save money. if 4 workers are selected at random what is the probability that at least 1 worker take the bus instead of the car to work? \n" ); document.write( "
Algebra.Com's Answer #279085 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi
\n" ); document.write( "Note: The probability of x successes in n trials is:
\n" ); document.write( "P = nCx* \"p%5Ex%2Aq%5E%28n-x%29\" where p and q are the probabilities of success and failure respectively.
\n" ); document.write( "In this case p(taking the bus)= .45 & q = .55
\n" ); document.write( "nCx = \"n%21%2F%28x%21%28n-x%21%29%29\"
\n" ); document.write( "P(out of 4, at least one takes bus) = 1-P(none taking bus) = 1 - (.55)^4
\n" ); document.write( "P(out of 4, at least one takes bus) = 1 - (.55)^4 = 1 - .0915 = .9085 \n" ); document.write( "
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