document.write( "Question 393166: in a shipment of 30 televisions, 4 are defective. if 3 television sets are randomly selected and tested without replacement, what is the probability that the three are defective? \n" ); document.write( "

Algebra.Com's Answer #279083 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "Note: The probability of x successes in n trials is: 
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document.write( "P = nCx*  where p and q are the probabilities of success and failure respectively. 
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document.write( "In this case let p(defective) = 4/30 = 2/15 & q = 7/15
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document.write( "nCx = 
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document.write( "P(3 chosen are all defective) = (2/15)^3 = .0024 \n" );
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