document.write( "Question 393090: A three digit number divisible by ten has a hundreds digit that is one less than its tens digit. The number is 52 times the sum of its digits. Find the number. \n" ); document.write( "
Algebra.Com's Answer #279047 by ankor@dixie-net.com(22740)\"\" \"About 
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A three digit number divisible by ten has a hundreds digit that is one less than its tens digit. The number is 52 times the sum of its digits. Find the number.
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\n" ); document.write( "We know the last digit = 0
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\n" ); document.write( "Let the number = 100x + 10y + 0
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\n" ); document.write( "\" a hundreds digit that is one less than its tens digit.\"
\n" ); document.write( "x = y - 1
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\n" ); document.write( "The number is 52 times the sum of its digits.
\n" ); document.write( "100x + 10y = 52(x+y)
\n" ); document.write( "100x + 10y = 52x + 5y
\n" ); document.write( "100x - 52x = 52y - 10y
\n" ); document.write( "48x = 42y
\n" ); document.write( "Replace x with (y-1)
\n" ); document.write( "48(y-1) = 42y
\n" ); document.write( "48y - 48 = 42y
\n" ); document.write( "48y - 42y = 48
\n" ); document.write( "6y = 48
\n" ); document.write( "y = \"48%2F6\"
\n" ); document.write( "y = 8
\n" ); document.write( "then
\n" ); document.write( "x = 7
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\n" ); document.write( "780 is the number
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\n" ); document.write( "confirm this in the statement:
\n" ); document.write( "\"The number is 52 times the sum of its digits.\"
\n" ); document.write( "780 = 52(7+8)
\n" ); document.write( "780 = 52(15)\r
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