document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=393087>Question 393087</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of the digits of a two-digit number is 14. if the digits are reversed, the number increased by 18. find the number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #279031 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=279031\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the sum of the digits of a two-digit number is 14. if the digits are reversed, the number increased by 18. find the number.<BR>\n" );
document.write( "..<BR>\n" );
document.write( "let digits be x & y  x in ten's place<BR>\n" );
document.write( "x+y=14.............1<BR>\n" );
document.write( "...<BR>\n" );
document.write( "10y+x= 10x+y+18<BR>\n" );
document.write( "9y-9x=18<BR>\n" );
document.write( "/9<BR>\n" );
document.write( "y-x=2.............2<BR>\n" );
document.write( "add (1)&(2)<BR>\n" );
document.write( "2y=16<BR>\n" );
document.write( "/2<BR>\n" );
document.write( "y=8<BR>\n" );
document.write( "so x= 6<BR>\n" );
document.write( "so the number is 68<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );