document.write( "Question 393061: x^2-4x+7=0 \n" ); document.write( "

Algebra.Com's Answer #279011 by edjones(8007) $\"\"$ $\"About$

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x^2-4x+7=0
\n" ); document.write( "x^2-4x =-7
\n" ); document.write( "x^2-4x+4=-7+4 completing the square.
\n" ); document.write( "(x-2)^2=-3
\n" ); document.write( "x-2=+-sqrt(-3)
\n" ); document.write( "x=2+-sqrt(3)i
\n" ); document.write( "x=2-sqrt(3)i, x=2+sqrt(3)i
\n" ); document.write( ".
\n" ); document.write( "Ed \n" ); document.write( "

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