document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=393005>Question 393005</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me in solving this problem<BR>\n" );
document.write( "Q) Solve for x<BR>\n" );
document.write( "   log(x+1)+log(x-1)=log 8  \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #278957 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=278957\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  log(x+1)+log(x-1)=log 8  <BR>\n" );
document.write( "==> log((x+1)(x-1)) = log 8<BR>\n" );
document.write( "==> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%28%28x%5E2+-+1%29%29+=+log+8 ALIGN=MIDDLE  ALT=\"log%28%28x%5E2+-+1%29%29+=+log+8\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "==> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2+-+1+=+8 ALIGN=MIDDLE  ALT=\"x%5E2+-+1+=+8\"   DISABLED_style= \"max-width:90%; height:auto;\" >, since the log function is one-to-one<BR>\n" );
document.write( "<==> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2+-+9+=+0 ALIGN=MIDDLE  ALT=\"x%5E2+-+9+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" >, or (x-3)(x+3) = 0, or x = -3, 3.  Since -3 will not satisfy the original equation, the final answer is x  =3. </SPAN>\n" );
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