document.write( "Question 392962: We are solving for \"p\"
\n" ); document.write( "Equation: 4 * sqrt (2p) + 1 = 24
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Algebra.Com's Answer #278951 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
We are solving for \"p\"
\n" ); document.write( "Equation: 4*sqrt(2p) + 1 = 24
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\n" ); document.write( "4*sqrt(2p) = 24 - 1
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\n" ); document.write( "4*sqrt(2p) = 23
\n" ); document.write( "Divide both sides by 4
\n" ); document.write( "\"sqrt%282p%29+=+23%2F4\"
\n" ); document.write( "square both sides
\n" ); document.write( "2p = \"%2823%2F4%29%5E2\"
\n" ); document.write( ":
\n" ); document.write( "2p = \"%28529%2F16%29\"
\n" ); document.write( "divide both sides by 2
\n" ); document.write( "p = \"%28529%2F32%29\"
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\n" ); document.write( "Response to student comment
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\n" ); document.write( "Check this using the decimal equiv in the original equation
\n" ); document.write( "529/32 = 16.53 = P
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\n" ); document.write( "4*sqrt(2p) + 1 = 24
\n" ); document.write( "4*sqrt(2(16.53)) + 1 = 24
\n" ); document.write( "4*sqrt(33.06) + 1 = 24
\n" ); document.write( "4*5.75 + 1 = 24
\n" ); document.write( "23 + 1 = 24; this checks out, all I can say is I interpreted the problem incorrectly.
\n" ); document.write( "Please let me know what answer you have; Carl
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