document.write( "Question 392824: solve the equation 3x+15=x^3+5x^2 algebraically for all values of x \n" ); document.write( "

Algebra.Com's Answer #278862 by Earlsdon(6294) $\"\"$ $\"About$

You can put this solution on YOUR website!
Solve for x:
\n" ); document.write( " $\"3x%2B15+=+x%5E3%2B5x%5E2\"$ Reformat to look like:
\n" ); document.write( " $\"x%5E3%2B5x%5E2-3x-15+=+0\"$ Factor.
\n" ); document.write( " $\"%28x%5E2-3%29%28x%2B5%29+=+0\"$ Apply the zero product rule.
\n" ); document.write( " $\"x%5E2-3+=+0\"$ or $\"x%2B5+=+0\"$ so...
\n" ); document.write( " $\"x%5E2+=3\"$ then $\"x+=+3\"$ and $\"x+=+-3\"$ also...
\n" ); document.write( " $\"x%2B5+=+0\"$ then $\"x+=+-5\"$ so...The values of x are:
\n" ); document.write( " $\"x+=+3\"$ , $\"x+=+-3\"$ , $\"x+=+-5\"$ \n" ); document.write( "

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