document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=42806>Question 42806</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello-\r<BR>\n" );
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document.write( "I'm stuck on an Algebra II problem and hope you can help.  The equation is as follows:\r<BR>\n" );
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document.write( "1/8 (3m-5)= 6/5 (6m-2)+5\r<BR>\n" );
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document.write( "I have never had a problem like this one.\r<BR>\n" );
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document.write( "I would appreciate your help and guidance.\r<BR>\n" );
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document.write( "Thank you very much.\r<BR>\n" );
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document.write( "Sam </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #27886 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=27886\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/8 (3m-5)= 6/5 (6m-2)+5 \r<BR>\n" );
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document.write( "Multiply both sides by 40 to get:<BR>\n" );
document.write( "5(3m-5) = 48(6m-2) + 200<BR>\n" );
document.write( "15m-25 = 288m-96 + 200<BR>\n" );
document.write( "-273m=25-96+200<BR>\n" );
document.write( "-273m=129<BR>\n" );
document.write( "m=-0.4725...\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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