document.write( "Question 392782: The length of a rectangle is six times its width.
\n" ); document.write( "If the area of the rectangle is 486yd^2 , find its perimeter
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Algebra.Com's Answer #278826 by stanbon(75887)\"\" \"About 
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The length of a rectangle is six times its width.
\n" ); document.write( "If the area of the rectangle is 486yd^2 , find its perimeter
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\n" ); document.write( "Equations:
\n" ); document.write( "L = 6W
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\n" ); document.write( "Area = LW
\n" ); document.write( "486 = 6W*W
\n" ); document.write( "6W^2 = 486
\n" ); document.write( "w^2 = 81
\n" ); document.write( "Positive solution:
\n" ); document.write( "W = 9 yd
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\n" ); document.write( "L = 6W = 6*9 = 54 yd
\n" ); document.write( "---
\n" ); document.write( "Perimeter = 2(L+W)
\n" ); document.write( "P = 2(9+54)
\n" ); document.write( "P = 2(63)
\n" ); document.write( "P = 126 yd.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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