document.write( "Question 392782: The length of a rectangle is six times its width.
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document.write( "If the area of the rectangle is 486yd^2 , find its perimeter \n" );
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Algebra.Com's Answer #278826 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The length of a rectangle is six times its width. \n" ); document.write( "If the area of the rectangle is 486yd^2 , find its perimeter \n" ); document.write( "------------------------------- \n" ); document.write( "Equations: \n" ); document.write( "L = 6W \n" ); document.write( "--- \n" ); document.write( "Area = LW \n" ); document.write( "486 = 6W*W \n" ); document.write( "6W^2 = 486 \n" ); document.write( "w^2 = 81 \n" ); document.write( "Positive solution: \n" ); document.write( "W = 9 yd \n" ); document.write( "--- \n" ); document.write( "L = 6W = 6*9 = 54 yd \n" ); document.write( "--- \n" ); document.write( "Perimeter = 2(L+W) \n" ); document.write( "P = 2(9+54) \n" ); document.write( "P = 2(63) \n" ); document.write( "P = 126 yd. \n" ); document.write( "============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |