document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=42746>Question 42746</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If I have an isosceles right triangle with the longest side having 48\", what is the length of the 2 remaining sides?  Please show the formula.....thank you very much. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #27879 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=27879\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Well the Pythagorean Theorem says<BR>\n" );
document.write( "a^2 + b^2 = c^2<BR>\n" );
document.write( "but since the triangle is isosceles, a = b, so we have<BR>\n" );
document.write( "a^2 + a^2 = 48^2<BR>\n" );
document.write( "2a^2 = 2304<BR>\n" );
document.write( "a^2 = 1152<BR>\n" );
document.write( "a = 24*sqrt(2) </SPAN>\n" );
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