document.write( "Question 392593: find the total no. of numbers less then 1000 & divisible by 5 that can be formed with the digits 0,1,2,3,4,5,6,7,8,9(none of the digits repeated). \n" ); document.write( "
Algebra.Com's Answer #278736 by sudhanshu_kmr(1152)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "less then 1000 means upto 3 digit numbers and at unit place either 0 or 5.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Single digit numbers...... only 5 i.e no. of ways = 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Two digit numbers...\r \n" ); document.write( "\n" ); document.write( " when 0 on unit place , no. of ways = 9 \n" ); document.write( " \n" ); document.write( " when 5 on unit place, no. of ways = 8 \n" ); document.write( " \n" ); document.write( " total no. of ways for 2 digit = 17 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Three digit numbers.. \n" ); document.write( " \n" ); document.write( " when 0 on unit place , no. of ways 9P2 = 9*8 = 72 \n" ); document.write( " \n" ); document.write( " when 5 on unit place, no. of ways = 9P2 - 8 = 64 \n" ); document.write( " ( in 8 numbers 0 will be on first place, so discard it)\r \n" ); document.write( "\n" ); document.write( " total no. of ways for 3 digit = 136\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " total no. of ways = 1 + 17 + 136 = 154 \n" ); document.write( " \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |