document.write( "Question 392593: find the total no. of numbers less then 1000 & divisible by 5 that can be formed with the digits 0,1,2,3,4,5,6,7,8,9(none of the digits repeated). \n" ); document.write( "
Algebra.Com's Answer #278736 by sudhanshu_kmr(1152)\"\" \"About 
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\n" ); document.write( "less then 1000 means upto 3 digit numbers and at unit place either 0 or 5.\r
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\n" ); document.write( "\n" ); document.write( "Single digit numbers...... only 5 i.e no. of ways = 1\r
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\n" ); document.write( "\n" ); document.write( "Two digit numbers...\r
\n" ); document.write( "\n" ); document.write( " when 0 on unit place , no. of ways = 9
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\n" ); document.write( " when 5 on unit place, no. of ways = 8
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\n" ); document.write( " total no. of ways for 2 digit = 17 \r
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\n" ); document.write( "\n" ); document.write( "Three digit numbers..
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\n" ); document.write( " when 0 on unit place , no. of ways 9P2 = 9*8 = 72
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\n" ); document.write( " when 5 on unit place, no. of ways = 9P2 - 8 = 64
\n" ); document.write( " ( in 8 numbers 0 will be on first place, so discard it)\r
\n" ); document.write( "\n" ); document.write( " total no. of ways for 3 digit = 136\r
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\n" ); document.write( "\n" ); document.write( " total no. of ways = 1 + 17 + 136 = 154
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