document.write( "Question 392655: Solve for x algebraically.
\n" ); document.write( "Square root of (x+1) + Square root of 2x=Square root of 5x+3
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Algebra.Com's Answer #278712 by Alan3354(69443)\"\" \"About 
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Solve for x algebraically.
\n" ); document.write( "Square root of (x+1) + Square root of 2x=Square root of 5x+3
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\n" ); document.write( "\"sqrt%28x%2B1%29+%2B+sqrt%282x%29+=+sqrt%285x%2B3%29\"
\n" ); document.write( "Square both sides
\n" ); document.write( "\"x%2B1+%2B+2x+%2B+2sqrt%282x%28x%2B1%29%29+=+5x%2B3\"
\n" ); document.write( "\"2sqrt%282x%5E2%2B2x%29+=+2x+%2B2\"
\n" ); document.write( "Square again
\n" ); document.write( "\"4%282x%5E2%2B2x%29+=+4x%5E2+%2B+8x+%2B+4\"
\n" ); document.write( "\"8x%5E2+%2B+8x+=+4x%5E2+%2B+8x+%2B+4\"
\n" ); document.write( "\"4x%5E2+-+4+=+0\"
\n" ); document.write( "x = ± 1\r
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