document.write( "Question 392604: a man is 20 years older than his son. In ten years, He will be twice as old as his son will then be. How old is each? \n" ); document.write( "
Algebra.Com's Answer #278660 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
a man is 20 years older than his son. In ten years, He will be twice as old as his son will then be. How old is each?
\n" ); document.write( "son = x years
\n" ); document.write( "father = x+20
\n" ); document.write( "...
\n" ); document.write( "after 10 years
\n" ); document.write( "son = x+10
\n" ); document.write( "father = x+20+10 = x+30 years
\n" ); document.write( "...
\n" ); document.write( "x+30=2(x+10)
\n" ); document.write( "x+30=2x+20
\n" ); document.write( "2x-x=30-20
\n" ); document.write( "x= 10 son's age
\n" ); document.write( "father's age = x+20 = 10+20 = 30 years
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( "
\n" );