document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=392592>Question 392592</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please explain or show work. this exactly how the question was written.\r<BR>\n" );
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document.write( "using the exact values,find the value of: \r<BR>\n" );
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document.write( "a.12 sin 30degrees - 6 tan 45 degress + sec 45 degrees / 52\r<BR>\n" );
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document.write( "b.sin 2A + tan 3A/2 - cos A + sec(A+15), when A= 30degrees\r<BR>\n" );
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document.write( "There were no parentheses and no exponents. please help by showing the work in  details. Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #278657 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=278657\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> using the exact values,find the value of: \r<BR>\n" );
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document.write( "a.12 sin 30degrees - 6 tan 45 degress + sec 45 degrees / 52\r<BR>\n" );
document.write( "\n" );
document.write( "b.sin 2A + tan 3A/2 - cos A + sec(A+15), when A= 30degrees\r<BR>\n" );
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document.write( "All you need to know is the value of the trigonometry functions at the special angles.  For this problem, you need to know the following:\r<BR>\n" );
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document.write( "sin 30 deg = 1/2<BR>\n" );
document.write( "tan 45 deg = 1<BR>\n" );
document.write( "sec 45 = sqrt(2)<BR>\n" );
document.write( "cos 30 =sqrt(3)/2<BR>\n" );
document.write( "sin 60 = sqrt(3)/2\r<BR>\n" );
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document.write( "a. 12 sin 30 deg - 6 tan 45 deg +sec 45 deg/52<BR>\n" );
document.write( "    = 12*1/2-6*1+sqrt(2)/52=6-6+sqrt(2)/52<BR>\n" );
document.write( "    =sqrt(2)/52\r<BR>\n" );
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document.write( "b.sin 2A + tan 3A/2 - cos A + sec(A+15)<BR>\n" );
document.write( "   =sin (2*30)+tan (3*30/2)-cos 30+sec(30+15)<BR>\n" );
document.write( "   = sin 60+tan 45-cos 30+sec 45<BR>\n" );
document.write( "   = sqrt(3)/2+1-sqrt(3)/2+sqrt(2)<BR>\n" );
document.write( "   = 1+sqrt(2)\r<BR>\n" );
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document.write( "  </SPAN>\n" );
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