document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=392588>Question 392588</A>: <I><SPAN STYLE=\"word-break: break-all;\"> factor 8b^2+24b+18 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #278638 by </B><A HREF=/tutors/aboutme.mpl?userid=haileytucki><B>haileytucki(390)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=haileytucki><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=haileytucki><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=278638\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 8b^(2)+24b+18\r<BR>\n" );
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document.write( "Factor out the GCF of 2 from each term in the polynomial.<BR>\n" );
document.write( "2(4b^(2))+2(12b)+2(9)\r<BR>\n" );
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document.write( "Factor out the GCF of 2 from 8b^(2)+24b+18.<BR>\n" );
document.write( "2(4b^(2)+12b+9)\r<BR>\n" );
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document.write( "In this problem (3)/(2)*(3)/(2)=9 and (3)/(2)+(3)/(2)=12, so insert (3)/(2) as the right hand term of one factor and (3)/(2) as the right-hand term of the other factor.<BR>\n" );
document.write( "2(b+(3)/(2))(b+(3)/(2))\r<BR>\n" );
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document.write( "Remove the fraction by multiplying the first term of the factor by the denominator of the second term.<BR>\n" );
document.write( "2(2b+3)(2b+3)\r<BR>\n" );
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document.write( "Combine the two common factors of (2b+3) by adding the exponents.<BR>\n" );
document.write( "2(2b+3)^(2) </SPAN>\n" );
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