document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=392580>Question 392580</A>: <I><SPAN STYLE=\"word-break: break-all;\"> factor x^3y+2x^2y^2+xy^3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #278631 by </B><A HREF=/tutors/aboutme.mpl?userid=haileytucki><B>haileytucki(390)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=haileytucki><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=haileytucki><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=278631\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^(3)y+2x^(2)y^(2)+xy^(3)\r<BR>\n" );
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document.write( "Factor out the GCF of xy from each term in the polynomial.<BR>\n" );
document.write( "xy(x^(2))+xy(2xy)+xy(y^(2))\r<BR>\n" );
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document.write( "Factor out the GCF of xy from x^(3)y+2x^(2)y^(2)+xy^(3).<BR>\n" );
document.write( "xy(x^(2)+2xy+y^(2))\r<BR>\n" );
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document.write( "In this problem 1*1=1 and 1+1=2, so insert 1 as the right hand term of one factor and 1 as the right-hand term of the other factor.<BR>\n" );
document.write( "xy(x+y)(x+y)\r<BR>\n" );
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document.write( "Combine the two common factors of (x+y) by adding the exponents.<BR>\n" );
document.write( "xy(x+y)^(2) </SPAN>\n" );
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