document.write( "Question 42764: I need answer to this asap. I'm just not getting these...\r
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document.write( "(9x+8) = (-3x+9)\r
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document.write( "The ( ) represent absolute value marks \n" );
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Algebra.Com's Answer #27859 by josmiceli(19441) You can put this solution on YOUR website! Here's the scoop. When you see the absolute value signs, \n" ); document.write( "do whatever's inside them as if they weren't there. \n" ); document.write( "Then, whatever the sign of the result is, make it POSITIVE. \n" ); document.write( "Also, abs(a + b) does not equal abs(a) + abs(b) \n" ); document.write( "You can see this by choosing a & b \n" ); document.write( "abs(3 + (-5)) =? abs(3) + abs(-5) \n" ); document.write( "2 not equal to 8 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "------------------------------ \n" ); document.write( " \n" ); document.write( "I applied a little logic here. It's a dumbed-down \n" ); document.write( "approach, but it works. \n" ); document.write( "x will be positive OR negative. It might be either one, \n" ); document.write( "so I'll try both cases. I'll say x = +a OR x = -a. \n" ); document.write( "I'll drop the absolute value sign and pick them up \n" ); document.write( "later. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "and the other possibility, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "check the 1st case, a = 1/12 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "this is TRUE \n" ); document.write( "Let's check the other possibility, a = -1/12 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "NOT TRUE \n" ); document.write( "So a = +1/12, and x = +1/12 \n" ); document.write( " |