document.write( "Question 392513: write in slope intercept form the equation of the line that passes through the given point and is perpendicular to the given line (-2,-2),y=x+1 \n" ); document.write( "
Algebra.Com's Answer #278580 by Alan3354(69443)\"\" \"About 
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A line and a point example.
\n" ); document.write( "Write in standard form the eqation of a line that satisfies the given conditions. Perpendicular to 9x+3y=36, through (1,2)
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\n" ); document.write( "Find the slope of the line. Do that by putting the equation in slope-intercept form, y = mx + b. That means solve for y.
\n" ); document.write( "9x+3y = 36
\n" ); document.write( "3y= - 9x + 36
\n" ); document.write( "y = -3x + 12
\n" ); document.write( "The slope, m = -3
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\n" ); document.write( "The slope of lines parallel is the same.
\n" ); document.write( "The slope of lines perpendicular is the negative inverse, m = +1/3
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\n" ); document.write( "Use y = mx + b and the point (1,2) to find b.
\n" ); document.write( "2 = (1/3)*1 + b
\n" ); document.write( "b = 5/3
\n" ); document.write( "The equation is y = (1/3)x + 5/3 (slope-intercept form)
\n" ); document.write( "x - 3y = -5 (standard form)
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\n" ); document.write( "For further assistance, or to check your work, email me via the thank you note, or at Moral Loophole@aol.com \n" ); document.write( "
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