document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=392213>Question 392213</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 19.	A motorist travelled 115 km on an expressway at an average speed of 92 km/h and another 45 minutes on the other roads. If the average speed for his whole journey was 80 km/h, how far did he travel on the other road?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #278542 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=278542\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 19. A motorist traveled 115 km on an expressway at an average speed of 92 km/h<BR>\n" );
document.write( " and another 45 minutes on the other roads.<BR>\n" );
document.write( " If the average speed for his whole journey was 80 km/h, how far did he travel on the other road? <BR>\n" );
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document.write( "Let d = distance  on the other roads<BR>\n" );
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document.write( "Change 45 min to .75 hrs<BR>\n" );
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document.write( "Write a time equation: time = dist/speed<BR>\n" );
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document.write( "express time + road time = total time<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=115%2F92 ALIGN=MIDDLE  ALT=\"115%2F92\"   DISABLED_style= \"max-width:90%; height:auto;\" > + .75 = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28%28d%2B115%29%29%2F80 ALIGN=MIDDLE  ALT=\"%28%28d%2B115%29%29%2F80\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Find least common multiple<BR>\n" );
document.write( "92: 2*2*23 <BR>\n" );
document.write( "80: 2*2*2*2*5<BR>\n" );
document.write( "LCM: 2*2*2*2*5*23 = 1840<BR>\n" );
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document.write( "Multiply equation by 1840, results:<BR>\n" );
document.write( "20(115) + .75(1840) = 23(d+115)<BR>\n" );
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document.write( "2300 + 1380 = 23d + 2645<BR>\n" );
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document.write( "3680 - 2645 = 23d<BR>\n" );
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document.write( "1035 = 23d<BR>\n" );
document.write( "d = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1035%2F23 ALIGN=MIDDLE  ALT=\"1035%2F23\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "d = 45 miles on other roads<BR>\n" );
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document.write( "Check solution by finding the times (total dist 115 + 45 = 160 mi)<BR>\n" );
document.write( "115/92 = 1.25 hrs<BR>\n" );
document.write( "other rd= .75 hrs<BR>\n" );
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document.write( "160/80 = 2.00 hrs<BR>\n" );
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