document.write( "Question 42758: A boxing ring is in the shape of a square, 20 ft on each side. How far apart are the fighters when they are in opposite corners of the ring? \n" ); document.write( "
Algebra.Com's Answer #27854 by Nate(3500)\"\" \"About 
You can put this solution on YOUR website!
Split the square in half diagonally to get a right angle.
\n" ); document.write( "\"a%5E2+%2B+b%5E2+=+c%5E2\"
\n" ); document.write( "\"sqrt%2820%5E2+%2B+20%5E2%29+=+c\"
\n" ); document.write( "\"sqrt%28400+%2B+400%29+=+c\"
\n" ); document.write( "\"sqrt%28800%29+=+c\"
\n" ); document.write( "\"sqrt%282%2A2%2A2%2A2%2A2%2A5%2A5%29+=+c\"
\n" ); document.write( "\"2%2A2%2A5%2Asqrt%282%29+=+c\"
\n" ); document.write( "\"20%2Asqrt%282%29+=+c\"
\n" ); document.write( "About 28 feet ....
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