document.write( "Question 42767: Roberto invested some money at 7%, and then invested $2000 more than twice this amount at 10%. His total annual income from the two investments was $3980. How much was invested at 10%? \n" ); document.write( "
Algebra.Com's Answer #27852 by Nate(3500)\"\" \"About 
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\"0.07x+%2B+0.1%282x+%2B+2000%29+=+3980\"
\n" ); document.write( "\"0.07x+%2B+0.2x+%2B+200+=+3980\"
\n" ); document.write( "\"0.27x+=+3780\"
\n" ); document.write( "\"x+=+14000\" at 7%
\n" ); document.write( "PLUG:
\n" ); document.write( "(2x + 2000)
\n" ); document.write( "(2(14000) + 2000)
\n" ); document.write( "(28000 + 2000)
\n" ); document.write( "$30,000 at 10%
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