document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=42728>Question 42728</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am trying to figure out how to evaluate the following expression:\r<BR>\n" );
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document.write( "2-(12/(-2+(2*2))I worked the problem by:\r<BR>\n" );
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document.write( "       -2+4(parenthesis)<BR>\n" );
document.write( "    12/2=6<BR>\n" );
document.write( "-2-6=8\r<BR>\n" );
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document.write( "Where aam I going wrong?\r<BR>\n" );
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document.write( "   \r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #27842 by </B><A HREF=/tutors/aboutme.mpl?userid=Nate><B>Nate(3500)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Nate><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=27842\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2-(12/(-2+(2*2))<BR>\n" );
document.write( "2-(12/(-2+(4))<BR>\n" );
document.write( "2-(12/(2))<BR>\n" );
document.write( "2-6<BR>\n" );
document.write( "-4 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );