document.write( "Question 392243: The probability that Barca wins a game with A.C. Milan is 0.2. Suppose they play 7 games. What is the probability that A.C. Milan wins at least four of the games? \n" ); document.write( "
Algebra.Com's Answer #278419 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi
\n" ); document.write( "Note: The probability of x successes in n trials is:
\n" ); document.write( "P = nCx* \"p%5Ex%2Aq%5E%28n-x%29\" where p and q are the probabilities of success and failure respectively.
\n" ); document.write( "In this case p = .2 and q = .8
\n" ); document.write( "nCx = \"n%21%2F%28x%21%28n-x%21%29%29\"
\n" ); document.write( "P(winning at least 4 of 7 games) = 1-P(no wins) -P(1 win) - P(2 wins) - P(3wins)
\n" ); document.write( "P(no wins) = (.8)^7 = .2097
\n" ); document.write( "P(1 win) = 7(.2)^1*(.8)^6 = .3670
\n" ); document.write( "P(2 wins)= 21(.2)^2*(.8)^5 = .2753
\n" ); document.write( "P(3wins)= 35(.2)^3*(.8)^4 = .1147
\n" ); document.write( "P(winning at least four games) = 1 -.9667 = .0333 \n" ); document.write( "
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