document.write( "Question 3959: mr.armstrong is saving his change in al large glass jar to buy a new hockey stick. yesterday,he counted the coins in the jar and found out that he only had quarters and dimes. there were a total of 345 coins.if he saved $75.90 how many quartes and dimes would he have?\r
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Algebra.Com's Answer #2784 by guapa(62)\"\" \"About 
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We have a total amount of 345 coins.Let q represent the number of quarters. Then 345-q represents the number of dimes. Use the following guideline to set up the equation:
\n" ); document.write( "Value of quarters in cent + Value of nickels in cents = Total value in cents
\n" ); document.write( " 25q + 10(345-q) = 7590
\n" ); document.write( "(25 because 1 quarter has 25 cents and 10 because 1 dime has 10 cents)
\n" ); document.write( "Now let's solve this equation:
\n" ); document.write( "25q+10(345-q)=7590
\n" ); document.write( "25q+3450-10q=7590 Now just combine like terms and substract 3450 from both sides.
\n" ); document.write( "15q+3450-3450=7590-3450
\n" ); document.write( "15q=4140
\n" ); document.write( "q= 4140/15
\n" ); document.write( "q=276
\n" ); document.write( "If q= 276, then 345-276=69, so he has 276 quarters and 69 nickels
\n" ); document.write( "Check:
\n" ); document.write( "276*25=6900/100 = $69
\n" ); document.write( "69*10=690/100 = $6.90
\n" ); document.write( "$69,00 + $6.90 = $75.90\r
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