document.write( "Question 392211: 32x + 23y = 10,100
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document.write( "12x + 14y = 5400\r
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document.write( "substituttion the varible. I selected equation 2 first to solve for y, but couldn't get y by itself. please help...\r
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document.write( "subtracted 12x from both sides of 12x + 14y = 5400 I got:
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document.write( "14y = 5400-12x....what is my next step?\r
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Algebra.Com's Answer #278383 by stanbon(75887) ![]() You can put this solution on YOUR website! \n" ); document.write( "32x + 23y = 10,100 \n" ); document.write( "12x + 14y = 5400\r \n" ); document.write( "\n" ); document.write( "substitute the varible. I selected equation 2 first to solve for y, but couldn't get y by itself. please help...\r \n" ); document.write( "\n" ); document.write( "subtracted 12x from both sides of 12x + 14y = 5400 I got: \n" ); document.write( "14y = 5400-12x....what is my next step? \n" ); document.write( "------------- \n" ); document.write( "y = (2700-6x)/7 \n" ); document.write( "-------- \n" ); document.write( "Substitute to get: \n" ); document.write( "32x + 23[2700-6x]/7 = 10100 \n" ); document.write( "32x + (62100-138x)/7 = 10100 \n" ); document.write( "--- \n" ); document.write( "Multiply thru by 7 to get: \n" ); document.write( "224x + 62100 - 138x = 7*10100 \n" ); document.write( "86x = 8600 \n" ); document.write( "x = 100 \n" ); document.write( "============= \n" ); document.write( "Substitute to solve for \"y\": \n" ); document.write( "y = (2700-6*100)/7 \n" ); document.write( "y = (2100)/7 \n" ); document.write( "y = 300 \n" ); document.write( "============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |