document.write( "Question 392188: Divide $128 into two parts such that one-third of the first part is less than
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Algebra.Com's Answer #278356 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!


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document.write( "Hi
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document.write( "$128 into two parts
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document.write( "Let x and ($128-x) represent the first part and second part respectively
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document.write( "If I am understanding Your question properly****
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document.write( "(1/3)x = (1/5)(128 -x) -$8   |multiplying each side by 15 so as all denominators= 1
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document.write( "   5x = 3($128-x) - $8*15
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document.write( "   5x = 3*128 - 3x - $8*15
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document.write( "   8x = $264
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document.write( "    x = $33, the first part.  The second part = $95    ($128-$33)\r
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document.write( "CHECKING our Answer
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document.write( " (1/3)$33 = (1/5)$95 -$8
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document.write( "      $11 = $19 - $8 \n" );
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