document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=42723>Question 42723</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Graph the function and state the domain and range.<BR>\n" );
document.write( "g(x)=x^2-2x-15<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #27834 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=27834\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Well from<BR>\n" );
document.write( "g(x) = x^2 - 2x - 15,<BR>\n" );
document.write( "we can find the vertex by looking at -b/2a for the x-coordinate and g(-b/2a) for the y-coordinate...thus we get<BR>\n" );
document.write( "-b/2a = 1 and<BR>\n" );
document.write( "g(1) = -16<BR>\n" );
document.write( "so our vertex is at (1, -16)<BR>\n" );
document.write( "Thus our parabola is of standard width, concave up, vertex at (1, -16) and has x-intercepts at (5, 0) and (-3, 0), which can be found by factoring g(x)...<BR>\n" );
document.write( "Its domain is all real numbers and the range would be g(x) &#8805; -16 </SPAN>\n" );
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