document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=392088>Question 392088</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many kilograms of pure salt must be added to 7 kg of a 30% salt solution in order to produce a 60% solution? Remember that pure salt is a 100% solution of salt. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #278322 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=278322\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How many kilograms of pure salt must be added to 7 kg of a 30% salt solution in order to produce a 60% solution? Remember that pure salt is a 100% solution of salt.<BR>\n" );
document.write( "salt 100 % x kgs<BR>\n" );
document.write( "solution 7 kgs 30%<BR>\n" );
document.write( "mix= 60% , (x+7) kgs<BR>\n" );
document.write( "...<BR>\n" );
document.write( "concentration equation<BR>\n" );
document.write( "100x+7*30= 60(x+7)<BR>\n" );
document.write( "100x+210=60x+420<BR>\n" );
document.write( "100x-60x=420-210<BR>\n" );
document.write( "40x=210<BR>\n" );
document.write( "/40<BR>\n" );
document.write( "x=5.25 kgs of salt required.<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );