document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=392145>Question 392145</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The diameter of the base of a cone is 14cm and its slant height is 25cm.what is its vertical height? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #278318 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=278318\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The diameter of the base of a cone is 14cm and its slant height is 25cm.what is its vertical height<BR>\n" );
document.write( "use pythagoras theorem since the height and the base are at right angles.<BR>\n" );
document.write( "25^2-7^2= (Slant height)^2<BR>\n" );
document.write( "576 = slangth height ^2<BR>\n" );
document.write( "slant height = sqrt 576 = 24 cm<BR>\n" );
document.write( "..<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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