document.write( "Question 392125: The denominator of a fraction is 9 more than the numerator. If the numerator is decreased by 3 and the denominator is increased by 3, the value of the resulting fraction is 1/4. What is the original fraction? \n" ); document.write( "
Algebra.Com's Answer #278304 by mananth(16946)![]() ![]() You can put this solution on YOUR website! The denominator of a fraction is 9 more than the numerator. If the numerator is decreased by 3 and the denominator is increased by 3, the value of the resulting fraction is 1/4. What is the original fraction? \n" ); document.write( "... \n" ); document.write( "numerator =x \n" ); document.write( "denominator = x+9 \n" ); document.write( "... \n" ); document.write( "fraction = \n" ); document.write( "... \n" ); document.write( " \n" ); document.write( "cross multiply \n" ); document.write( "4(x-3)=(x+12) \n" ); document.write( "4x-12=x+12 \n" ); document.write( "add 12 \n" ); document.write( "4x=x+12+12 \n" ); document.write( "4x=x+24 \n" ); document.write( "add -x \n" ); document.write( "4x-x=24 \n" ); document.write( "3x=24 \n" ); document.write( "/3 \n" ); document.write( "x=8 the numerator \n" ); document.write( "x+9= 17 the denominator \n" ); document.write( ".. \n" ); document.write( "The fraction is \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |