document.write( "Question 392125: The denominator of a fraction is 9 more than the numerator. If the numerator is decreased by 3 and the denominator is increased by 3, the value of the resulting fraction is 1/4. What is the original fraction? \n" ); document.write( "
Algebra.Com's Answer #278304 by mananth(16946)\"\" \"About 
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The denominator of a fraction is 9 more than the numerator. If the numerator is decreased by 3 and the denominator is increased by 3, the value of the resulting fraction is 1/4. What is the original fraction?
\n" ); document.write( "...
\n" ); document.write( "numerator =x
\n" ); document.write( "denominator = x+9
\n" ); document.write( "...
\n" ); document.write( "fraction = \"x%2F%28x%2B9%29\"
\n" ); document.write( "...
\n" ); document.write( "\"%28x-3%29%2F%28x%2B12%29=1%2F4\"
\n" ); document.write( "cross multiply
\n" ); document.write( "4(x-3)=(x+12)
\n" ); document.write( "4x-12=x+12
\n" ); document.write( "add 12
\n" ); document.write( "4x=x+12+12
\n" ); document.write( "4x=x+24
\n" ); document.write( "add -x
\n" ); document.write( "4x-x=24
\n" ); document.write( "3x=24
\n" ); document.write( "/3
\n" ); document.write( "x=8 the numerator
\n" ); document.write( "x+9= 17 the denominator
\n" ); document.write( "..
\n" ); document.write( "The fraction is \"+8%2F17\"
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\n" ); document.write( "m.ananth@hotmail.ca
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