document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=42646>Question 42646</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find sec &#952; if tan &#952; =1/4 and 180° < &#952; < 270°.\r<BR>\n" );
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document.write( "Thank You  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #27830 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=27830\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let q be theta...<BR>\n" );
document.write( "We know that tan^2 q + 1 = sec^2 q so that<BR>\n" );
document.write( "sec^2 q = 1 + (1/4)^2 = 1 + 1/16 = 17/16<BR>\n" );
document.write( "sec q = sqrt(17) / 4<BR>\n" );
document.write( "But in the 3rd quadrant sec q, like cos q, is negative, so<BR>\n" );
document.write( "sec q = -sqrt(17) / 4 </SPAN>\n" );
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