document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=42648>Question 42648</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find cos&#952; if sin&#952; = 3/5 and 90° < &#952; <180°.\r<BR>\n" );
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document.write( "Thank You  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #27827 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=27827\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let q be theta...<BR>\n" );
document.write( "Since sin^2 q + cos^2 q = 1, we know that<BR>\n" );
document.write( "cos^2 q = 1 - sin^2 q<BR>\n" );
document.write( "cos^2 q = 1 - (3/5)^2<BR>\n" );
document.write( "cos^2 q = 1 - 9/25 = 16/25 and then<BR>\n" );
document.write( "cos q = 4/5<BR>\n" );
document.write( "But in the 2nd quadrant, cos q is negative so the answer is<BR>\n" );
document.write( "-4/5 </SPAN>\n" );
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