document.write( "Question 392016: a company wants a solution of 200 nitogen at 7.7% it has a nitogren mixture of 7% and 8%. how much of each will it need to make the 7.7 % solution \n" ); document.write( "
Algebra.Com's Answer #278236 by Earlsdon(6294)\"\" \"About 
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Let x = the required amount of 7% nitrogen(?) mixture, then (200-x) = the required amount of 8% nitrogen mixture. The sum of these two amounts are to equal 200 units of 7.7% nitrogen solution. The equation, after converting the percentages to their decimal eqivalents is:
\n" ); document.write( "\"x%280.07%29%2B%28200-x%29%280.08%29+=+200%280.077%29\" Solve for x.
\n" ); document.write( "\"0.07x%2B16-0.08x+=+15.4\" Simplify.
\n" ); document.write( "\"-0.01x%2B16+=+15.4\" Subtract 16.
\n" ); document.write( "\"-0.01x+=+-0.6\" Divide by -0.01
\n" ); document.write( "\"x+=+60\"
\n" ); document.write( "The company will need to mix 60 units of the 7% nitrogen solution with 140 (200-60) units of the 8% nitrogen solution to obtain 200 units of 7.7 nitrogen mixture.
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