document.write( "Question 392016: a company wants a solution of 200 nitogen at 7.7% it has a nitogren mixture of 7% and 8%. how much of each will it need to make the 7.7 % solution \n" ); document.write( "
Algebra.Com's Answer #278236 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! Let x = the required amount of 7% nitrogen(?) mixture, then (200-x) = the required amount of 8% nitrogen mixture. The sum of these two amounts are to equal 200 units of 7.7% nitrogen solution. The equation, after converting the percentages to their decimal eqivalents is: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The company will need to mix 60 units of the 7% nitrogen solution with 140 (200-60) units of the 8% nitrogen solution to obtain 200 units of 7.7 nitrogen mixture. \n" ); document.write( " |