document.write( "Question 391974: The speed of train A is 14mph slower than the speed of train B. Train A travels 190mi in the same time it takes train B to travel 260mi. Finf the speed of each train \n" ); document.write( "
Algebra.Com's Answer #278162 by josmiceli(19441)\"\" \"About 
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For train A:
\n" ); document.write( "\"d%5BA%5D+=+%28r+-+14%29%2At%5BA%5D\"
\n" ); document.write( "For train B:
\n" ); document.write( "\"d%5BB%5D+=+r%2At%5BB%5D\"
\n" ); document.write( "-------------
\n" ); document.write( "given:
\n" ); document.write( "\"d%5BA%5D+=+190\" mi
\n" ); document.write( "\"d%5BB%5D+=+260\" mi
\n" ); document.write( "\"t%5BA%5D+=+t%5BB%5D\" hr
\n" ); document.write( "(since these times are equal, I'll call them both \"t\")
\n" ); document.write( "--------------
\n" ); document.write( "I'll rewrite the equations:
\n" ); document.write( "(1) \"190+=+%28r+-+14%29%2At\"
\n" ); document.write( "(2) \"260+=+r%2At\"
\n" ); document.write( "This is 2 equations and 2 unknowns, so it's solvable
\n" ); document.write( "(1) \"190+=+r%2At+-+14t\"
\n" ); document.write( "(2) \"260+=+r%2At\"
\n" ); document.write( "Substitute (2) into (1):
\n" ); document.write( "(1) \"190+=+260+-+14t\"
\n" ); document.write( "\"14t+=+70\"
\n" ); document.write( "\"t+=+5\" hrs
\n" ); document.write( "Plug this back into (2):
\n" ); document.write( "\"260+=+r%2A5\"
\n" ); document.write( "\"r+=+52\" mi/hr
\n" ); document.write( "\"r+-+14+=+38\" mi/hr
\n" ); document.write( "Train A's speed is 38 mi/hr
\n" ); document.write( "Train B's speed is 52 mi/hr
\n" ); document.write( "
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