document.write( "Question 391959: Fins the vertices of the hyperbola defined by the equation.The equation is (y+3)^2/49 - (x-9)/64 = 1. it tells be to put my answer in this form (x1,y1) (y2,y2).I keep getting this question wrong could someone help. \n" ); document.write( "

Algebra.Com's Answer #278155 by Edwin McCravy(20056) $\"\"$ $\"About$

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Find the vertices of the hyperbola defined by the equation.The equation is $\"%28y%2B3%29%5E2%2F49+-+%28x-9%29%5E2%2F64+=+1\"$ . it tells be to put my answer in this form (x1,y1) (y2,y2).I keep getting this question wrong could someone help.
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document.write( "It is in the standard form\r\n" );
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document.write( "We can tell that the hyperbola opens upward and downward because\r\n" );
document.write( "the term in y comes first in the standard equation.\r\n" );
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document.write( "where the center is  = \r\n" );
document.write( "The length of the semi-transverse axis is  =  = 7\r\n" );
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document.write( "The vertices are 7 units above and below the center (9,-3), so\r\n" );
document.write( "we add to and subtract 7 from the y-ccordinate of the center. So the\r\n" );
document.write( "vertices are \r\n" );
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document.write( "(9,-3+7) and (9,-3-7) or simplifying:\r\n" );
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document.write( "(9,4) and (9,-10)\r\n" );
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document.write( "But since you could have been asked more than that I'll go into\r\n" );
document.write( "some more detail that may help you in other hyperbola problems. \r\n" );
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document.write( "The length of the semi-conjugate axis is  =  = 8\r\n" );
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document.write( "First let's plot the center:\r\n" );
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document.write( "Now let's draw the transverse and conjugate axes by drawing\r\n" );
document.write( "1.  a vertical line a=7 units above the center.\r\n" );
document.write( "2.  a vertical line a=7 units below the center.\r\n" );
document.write( "3.  a horizontal line b=8 units left of the center.\r\n" );
document.write( "3.  a horizontal line b=8 units right of the center.\r\n" );
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document.write( "The green vertical line is the complete transverse axis which goes from\r\n" );
document.write( "vertex to vertex. The horizontal line is the complete conjugate axis.\r\n" );
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document.write( "Next we draw the defining rectangle which has the transverse and conjugate\r\n" );
document.write( "axes bisecting the sides of the rectangle:\r\n" );
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document.write( "Next we draw the two asymptotes, by drawing and extending the\r\n" );
document.write( "diagonals of the defining rectangle:\r\n" );
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document.write( "Now we can sketch in the hyperbola:\r\n" );
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document.write( "You could have been asked to graph the hyperbola.  You could\r\n" );
document.write( "also have been asked to find the equations of the asymptotes, which\r\n" );
document.write( "you could do because you have points that they pass through. You\r\n" );
document.write( "could also be asked to find the foci.  Then you'd have to find c\r\n" );
document.write( "from the equation c² = a² + b².\r\n" );
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document.write( "Edwin

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