document.write( "Question 391825: Write an equation of a line in standard form that passes through (6, -5) perpendicular to the line whose equation is 3x-1/5y=3.
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document.write( "Can you help me solve? \n" );
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Algebra.Com's Answer #278104 by jjordan95(63)![]() ![]() You can put this solution on YOUR website! In order to find a perpendicular line, you need the equation in the form: \n" ); document.write( "\n" ); document.write( "So convert your function into the form mentioned above: \n" ); document.write( " \n" ); document.write( "= \n" ); document.write( "= \n" ); document.write( "\n" ); document.write( "Next, we take the inverse reciprocal of the slope (m is the slope in the equation y=mx+b.\r \n" ); document.write( "\n" ); document.write( "The reciprocal of 15 is 1/15, to invert the number, simply make it the opposite sign that it currently is (positive turns to negative, and vice-versa). Therefore, the slope of the line perpendicular to y=15x-15, is -1/15. \n" ); document.write( "The perpendicular line, now has the equation: \n" ); document.write( "Now, we must solve for b. To solve for b, we simply plug in the x and y values from the point above. (x,y), (6,-5).\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now plug b back into the equation and you have your answer: \n" ); document.write( " |