document.write( "Question 391825: Write an equation of a line in standard form that passes through (6, -5) perpendicular to the line whose equation is 3x-1/5y=3.
\n" ); document.write( "Can you help me solve?
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Algebra.Com's Answer #278104 by jjordan95(63)\"\" \"About 
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In order to find a perpendicular line, you need the equation in the form: \"y=mx%2Bb\"\r
\n" ); document.write( "\n" ); document.write( "So convert your function into the form mentioned above:
\n" ); document.write( "\"3x-%281%2F5%29y=3\"
\n" ); document.write( "=\"%28-1%2F5%29y=3-3x\"
\n" ); document.write( "=\"y=15x-15\"\r
\n" ); document.write( "\n" ); document.write( "Next, we take the inverse reciprocal of the slope (m is the slope in the equation y=mx+b.\r
\n" ); document.write( "\n" ); document.write( "The reciprocal of 15 is 1/15, to invert the number, simply make it the opposite sign that it currently is (positive turns to negative, and vice-versa). Therefore, the slope of the line perpendicular to y=15x-15, is -1/15.
\n" ); document.write( "The perpendicular line, now has the equation: \"y=%28-1%2F15%29x%2Bb\"
\n" ); document.write( "Now, we must solve for b. To solve for b, we simply plug in the x and y values from the point above. (x,y), (6,-5).\r
\n" ); document.write( "\n" ); document.write( "\"-5=%28-1%2F15%29%286%29%2Bb\"
\n" ); document.write( "\"-5=-6%2F15%2Bb\"
\n" ); document.write( "\"-5%2B6%2F15=b\"
\n" ); document.write( "\"-75%2F15%2B6%2F15=b\"
\n" ); document.write( "\"-69%2F15=b\"\r
\n" ); document.write( "\n" ); document.write( "Now plug b back into the equation and you have your answer:
\n" ); document.write( "\"highlight%28y=%28-1%2F15%29x-69%2F15%29\"
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