document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=391902>Question 391902</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Steve is three times as old as Theresa. In four years he will be twice as old as she will be. How old is each now? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #278103 by </B><A HREF=/tutors/aboutme.mpl?userid=AnubhavRane><B>AnubhavRane(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=AnubhavRane><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=278103\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let,<BR>\n" );
document.write( "S = Steve's age today<BR>\n" );
document.write( "T = Teresa's age today\r<BR>\n" );
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document.write( "After four years their ages will be-<BR>\n" );
document.write( "Steve : S + 4<BR>\n" );
document.write( "Teresa: T + 4\r<BR>\n" );
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document.write( "Now let's write their relationships<BR>\n" );
document.write( "Today        : S = 3T             ....(I)<BR>\n" );
document.write( "After 4 years: S + 4 = 2(T + 4)   ....(II)\r<BR>\n" );
document.write( "\n" );
document.write( "Let's substitute S = 3T from equation (I) into equation (II)<BR>\n" );
document.write( "3T + 4  = 2(T + 4)<BR>\n" );
document.write( "3T + 4  = 2T + 8<BR>\n" );
document.write( "3T - 2T = 8 - 4<BR>\n" );
document.write( "T = 4 years ... this is Tersa's age today<BR>\n" );
document.write( "So Steve's age must be 3T = 3 x 4 = 12 years </SPAN>\n" );
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